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Description
You are given n points on a line with their coordinates xi. Find the point x so the sum of distances to the given points is minimal.
The first line contains integer n (1 ≤ n ≤ 3·105) — the number of points on the line.
The second line contains n integers xi ( - 109 ≤ xi ≤ 109) — the coordinates of the given n points.
Print the only integer x — the position of the optimal point on the line. If there are several optimal points print the position of the leftmost one. It is guaranteed that the answer is always the integer.
4
1 2 3 4
2
题意：找出一个点，以外的点距离它之和最小
解法：排序找中间的数
#include<bits/stdc++.h>
using namespace std;
int a[3*100005];
int main()
{
int n;
cin>>n;
for(int i=1;i<=n;i++)
{
cin>>a[i];
}
sort(a+1,a+1+n);
if(n==1)
{
cout<<a[1]<<endl;
}
else if(n&1)
{
cout<<a[n/2+1]<<endl;
}
else
{
cout<<a[n/2]<<endl;
}
return 0;
}
Educational Codeforces Round 16 B
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原文地址：http://www.cnblogs.com/yinghualuowu/p/5802003.html
