标签:des style blog http color os io 数据
题目链接:http://acdream.info/problem?pid=1157
由3钟类型操作:
1)D L R(1 <= L <= R <= 1000000000) 增加一条线段[L,R]
2)C i (1-base) 删除第i条增加的线段,保证每条插入线段最多插入一次,且这次删除操作一定合法
3) Q L R(1 <= L <= R <= 1000000000) 查询目前存在的线段中有多少条线段完全包含[L,R]这个线段,线段X被线段Y完全包含即LY <= LX
<= RX <= RY)
给出N,接下来N行,每行是3种类型之一
多组数据,每组数据N
接下来N行,每行是三种操作之一(1 <= N <= 10^5)
1 #include <iostream> 2 #include <algorithm> 3 #include <cstring> 4 #include <cstdio> 5 using namespace std; 6 7 const int MAXN = 200010; 8 9 int hashmap[MAXN], hcnt; 10 int tree[MAXN]; 11 12 int hash(int x) { 13 return lower_bound(hashmap, hashmap + hcnt, x) - hashmap + 1; 14 } 15 16 inline int lowbit(int x) { 17 return x & -x; 18 } 19 20 void modify(int k, int val) { 21 while(k <= hcnt) { 22 tree[k] += val; 23 k += lowbit(k); 24 } 25 } 26 27 int get_sum(int k) { 28 int res = 0; 29 while(k) { 30 res += tree[k]; 31 k -= lowbit(k); 32 } 33 return res; 34 } 35 36 struct Node { 37 int v, l, r, id; 38 Node() {} 39 Node(int v, int l, int r, int id): v(v), l(l), r(r), id(id) {} 40 bool operator < (const Node &rhs) const { 41 if(r != rhs.r) return r > rhs.r; 42 if(l != rhs.l) return l < rhs.l; 43 return (v == 0) < (rhs.v == 0); 44 } 45 }; 46 47 bool cmp_id(const Node &a, const Node &b) { 48 return a.id < b.id; 49 } 50 51 Node p[MAXN]; 52 int ans[MAXN], tl[MAXN], tr[MAXN]; 53 int n; 54 55 void solve(int l, int r) { 56 if(l == r) return ; 57 int mid = (l + r) >> 1; 58 solve(l, mid); 59 solve(mid + 1, r); 60 sort(p + l, p + r + 1); 61 for(int i = l; i <= r; ++i) { 62 if(p[i].id <= mid) { 63 if(p[i].v) modify(p[i].l, p[i].v); 64 } else { 65 if(!p[i].v) ans[p[i].id] += get_sum(p[i].l); 66 } 67 } 68 for(int i = l; i <= r; ++i) { 69 if(p[i].id <= mid && p[i].v) modify(p[i].l, -p[i].v); 70 } 71 sort(p + l, p + r + 1, cmp_id); 72 } 73 74 int main() { 75 while(scanf("%d", &n) != EOF) { 76 int tcnt = 0; hcnt = 0; 77 char c; 78 for(int i = 1, t, u; i <= n; ++i) { 79 scanf(" %c", &c); 80 if(c == ‘D‘) { 81 scanf("%d%d", &t, &u); 82 p[i] = Node(1, t, u, i); 83 hashmap[hcnt++] = t; hashmap[hcnt++] = u; 84 tl[++tcnt] = t; tr[tcnt] = u; 85 } 86 if(c == ‘C‘) { 87 scanf("%d", &t); 88 p[i] = Node(-1, tl[t], tr[t], i); 89 } 90 if(c == ‘Q‘) { 91 scanf("%d%d", &t, &u); 92 p[i] = Node(0, t, u, i); 93 hashmap[hcnt++] = t; hashmap[hcnt++] = u; 94 } 95 } 96 sort(hashmap, hashmap + hcnt); 97 hcnt = unique(hashmap, hashmap + hcnt) - hashmap; 98 for(int i = 1; i <= n; ++i) { 99 p[i].l = hash(p[i].l); p[i].r = hash(p[i].r); 100 } 101 memset(ans + 1, 0, n * sizeof(int)); 102 solve(1, n); 103 for(int i = 1; i <= n; ++i) 104 if(p[i].v == 0) printf("%d\n", ans[i]); 105 } 106 }
ACdream 1157 Segments(CDQ分治),布布扣,bubuko.com
标签:des style blog http color os io 数据
原文地址:http://www.cnblogs.com/oyking/p/3901715.html