标签：
Given a string s consists of upper/lower-case alphabets and empty space characters ‘ ‘, return the length of last word in the string.
If the last word does not exist, return 0.
Note: A word is defined as a character sequence consists of non-space characters only.
For example, Given s = "Hello World", return 5.
Tags: String
字符串操作
class Solution { public: int lengthOfLastWord(string s) { string::size_type pos = s.find_last_not_of(‘ ‘); if (pos != s.npos) { string sTemp = s.substr(0, pos+1); pos = sTemp.rfind(‘ ‘); if (pos != sTemp.npos) { return sTemp.length() - pos - 1; } else { return sTemp.length(); } } return 0; } };
标签：
原文地址：http://www.cnblogs.com/whl2012/p/5812023.html
