标签:des style os io 文件 数据 for div
3 3 0 1 1 0 2 3 1 2 1 0 2 3 1 0 1 1 1 2
2 -1
迪科斯彻的模板题。
#include <stdio.h> #include <string.h> #include <algorithm> #include <math.h> #include <stack> #define lson o<<1, l, m #define rson o<<1|1, m+1, r using namespace std; typedef long long LL; const int maxn = 205; const int MAX = 0x3f3f3f3f; const int mod = 1000000007; int m, n, st, en; int g[205][205], dij[205], vis[205]; void DIJ() { memset(dij, MAX, sizeof(dij)); memset(vis, 0, sizeof(vis)); dij[st] = 0; for(int i = 0; i < n; i++){ int tmp = MAX, pos; for(int j = 0; j < n; j++) if(vis[j] == 0 && dij[j] < tmp) { tmp = dij[j]; pos = j; } vis[pos] = 1; for(int j = 0; j < n; j++) if(vis[j] == 0 &&dij[pos] + g[pos][j] < dij[j]) dij[j] = dij[pos] + g[pos][j]; } } int main() { while(~scanf("%d%d", &n, &m)) { memset(g, MAX, sizeof(g)); for(int i = 1; i <= m; i++) { int a, b, c; scanf("%d%d%d", &a, &b, &c) ; if(c > g[a][b]) continue; g[a][b] = g[b][a] = c; } scanf("%d%d", &st, &en); DIJ(); if(vis[en]) printf("%d\n", dij[en]); else printf("-1\n"); } return 0; }
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标签:des style os io 文件 数据 for div
原文地址:http://blog.csdn.net/u013923947/article/details/38464849