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数学图形之超球

时间:2014-08-10 10:22:30      阅读:580      评论:0      收藏:0      [点我收藏+]

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超球,自然界有很多果实属于超球的形状.之前曾经写过关于超圆的文章:数学图形(1.44)超圆, 这篇文章将对其扩展一下,由超圆的二维曲线转化为超球三维曲面.

超圆就是方程式:x^a+y^b= c          生成的图形.当a==b==2时,为一个圆.

超椭圆是方程式:m*x^a+n*y^b= c 生成的图形.当a==b==2时,为一个椭圆.

那么超球则是如下定义:

超球的方程式:x^a+y^b+z^c= d  

超椭球的方程式:m*x^a+n*y^b+k*z^c= d

我使用自己定义语法的脚本代码生成超球图形.相关软件参见:数学图形可视化工具,该软件免费开源.QQ交流群: 367752815

(1)将超圆沿X轴或Y轴旋转生成的图形也是超球的一种

vertices = D1:100 D2:100

u = from (-PI/2) to (PI/2)  D1
v = from 0 to (2*PI) D2

a = rand2(0.1, 4)
b = rand2(0.1, 4)
r = 10.0

x = r*pow_sign(sin(u), a)
n = r*pow_sign(cos(u), b)

y = n*cos(v)
z = n*sin(v)
vertices = D1:100 D2:100

u = from 0 to (PI) D1
v = from 0 to (2*PI) D2

a = rand2(0.1, 4)
b = rand2(0.1, 4)
r = 10.0

n = r*pow_sign(sin(u), a)
y = r*pow_sign(cos(u), b)

x = n*cos(v)
z = n*sin(v)

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(2)超球面(瘦)

vertices = D1:100 D2:100

u = from 0 to (2*PI) D1
v = from (-PI*0.5) to (PI*0.5) D2

a = 10

m = rand2(1, 5)

x = a*pow_sign(cos(u)*cos(v), m)
y = a*pow_sign(sin(v), m)
z = a*pow_sign(sin(u)*cos(v), m)

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(3)超球面(胖)

vertices = D1:100 D2:100

u = from 0 to (2*PI) D1
v = from (-PI*0.5) to (PI*0.5) D2

a = 10

m = rand2(0.1, 1)

x = a*pow_sign(cos(u)*cos(v), m)
y = a*pow_sign(sin(v), m)
z = a*pow_sign(sin(u)*cos(v), m)

bubuko.com,布布扣

(4)超球面(双参)

vertices = D1:100 D2:100

u = from 0 to (2*PI) D1
v = from (-PI*0.5) to (PI*0.5) D2

a = 10

m = rand2(0.2, 5)
n = rand2(0.2, 5)

x = a*pow_sign(cos(u)*cos(v), m)
y = a*pow_sign(sin(v), n)
z = a*pow_sign(sin(u)*cos(v), m)

bubuko.com,布布扣

(5)超球面(三参)

vertices = D1:100 D2:100

u = from 0 to (2*PI) D1
v = from (-PI*0.5) to (PI*0.5) D2

r = 10

a = rand2(0.2, 5)
b = rand2(0.2, 5)
c = rand2(0.2, 5)

x = r*pow_sign(cos(u)*cos(v), a)
y = r*pow_sign(sin(v), b)
z = r*pow_sign(sin(u)*cos(v), c)

bubuko.com,布布扣

(6)超椭球面

vertices = D1:100 D2:100

u = from (-PI*0.5) to (PI*0.5) D1
v = from (-PI) to (PI) D2

a = rand2(1, 5)
b = rand2(1, 5)
c = rand2(1, 5)
m = 5
n = 3

x = a*(cos(u)^m)*(cos(v)^n)
z = b*(cos(u)^m)*(sin(v)^n)
y = c*(sin(u)^m)

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vertices = D1:100 D2:100
u = from (-PI*0.5) to (PI*0.5) D1
v = from (-PI) to (PI) D2
a = rand2(1, 5)
b = rand2(1, 5)
c = rand2(1, 5)
m = 0.6
n = 0.3
x = a*(pow_sign(cos(u), m))*(pow_sign(cos(v),n))
z = b*(pow_sign(cos(u),m))*(pow_sign(sin(v),n))
y = c*(pow_sign(sin(u),m))

bubuko.com,布布扣

 

数学图形之超球,布布扣,bubuko.com

数学图形之超球

标签:style   blog   http   color   使用   os   2014   div   

原文地址:http://www.cnblogs.com/WhyEngine/p/3902435.html

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