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转自:http://www.cnblogs.com/youxin/p/3303172.html
2s = s + nrs= nr
设整个链表长L,入口环与相遇点距离为x,起点到环入口点的距离为a。a + x = nra + x = (n – 1)r +r = (n-1)r + L - aa = (n-1)r + (L – a – x)
(转)求单链表是否有环,环入口和环长
原文地址:http://www.cnblogs.com/wrencai/p/5815805.html