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链接:http://acm.hust.edu.cn/vjudge/problem/19641
分析:车厢符合后进先出的原则,因此是一个栈。
1 #include <cstdio> 2 #include <stack> 3 using namespace std; 4 5 const int maxn = 1000 + 10; 6 7 int n, target[maxn]; 8 9 int main() { 10 while (scanf("%d", &n) == 1 && n) { 11 while (scanf("%d", &target[1]) && target[1]) { 12 stack<int> s; 13 for (int i = 2; i <= n; i++) scanf("%d", &target[i]); 14 int A = 1, B = 1; 15 bool ok = true; 16 while (B <= n) { 17 if (A == target[B]) { A++; B++; } 18 else if (!s.empty() && s.top() == target[B]) { s.pop(); B++; } 19 else if (A <= n) s.push(A++); 20 else { ok = false; break; } 21 } 22 printf("%s\n", ok ? "Yes" : "No"); 23 } 24 printf("\n"); 25 } 26 return 0; 27 }
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原文地址:http://www.cnblogs.com/XieWeida/p/5827615.html