1 //2016.9.1
 2 #include <iostream>
 3 #include <cstdio>
 4 #include <cstring>
 5 
 6 using namespace std;
 7 
 8 int n, a[105], b[105], c[105], book[105][12], dit[105][5], vis[12], dit2[5], ans;
 9 //book[i]记录a[i]出现了哪些数字,dit[i]记录a[i]不同位上的数字,vis记录x出现了哪些数字,dit2记录x不同位上的数字
10 
11 bool judge(int x)
12 {
13     int cntb, cntc, pos = 0;
14     memset(vis, 0, sizeof(vis));
15     memset(dit2, 0, sizeof(dit2));
16     while(x)
17     {
18         dit2[pos] = x%10;
19         vis[x%10]++;
20         x /= 10;
21         pos++;                                                            
22     }
23     for(int i = 0; i < n; i++)
24     {
25         cntb = cntc = 0;
26         for(int j = 0; j < 4; j++)
27               if(dit2[j] == dit[i][j])cntc++;
28         if(cntc != c[i])return false;
29         for(int j = 0; j < 10; j++)
30                 if(vis[j] && book[i][j])
31                 cntb += min(vis[j], book[i][j]);
32         if(cntb != b[i])return false;
33     }
34     return true;
35 }
36 
37 int main()
38 {
39     int cnt;
40     while(scanf("%d", &n)!=EOF && n)
41     {
42         cnt = 0;
43         memset(book, 0, sizeof(book));
44         for(int i = 0; i < n; i++)
45         {
46             scanf("%d%d%d", &a[i], &b[i], &c[i]);
47             int tmp = a[i], count = 0;
48             while(tmp)
49             {
50                 book[i][tmp%10]++;
51                 dit[i][count++] = tmp%10;
52                 tmp /= 10;
53             }
54         }
55         for(int i = 1000; i < 10000; i++)//暴力枚举所有四位数
56               if(judge(i))
57             {
58                 ans = i;
59                 cnt++;
60             }
61         if(cnt==1)printf("%d\n", ans);
62         else printf("Not sure\n");//如果答案不唯一，则不确定
63     }
64     return 0;
65 }