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题目链接 http://acm.hust.edu.cn/vjudge/problem/19411
解题思路
快速幂, 筛法求素数。
代码
#include<iostream> #include<cstdio> #include<string.h> #include<cmath> typedef long long ll; using namespace std; const int maxS = 65005; bool isPrime[maxS]; ll PowMod(int a, int b, int c) { ll result = 1; ll base = a % c; while(b) { if(b & 1) result = (result * base) % c; base = (base * base) % c; b = b >> 1; } return result; } int main() { int flag, n, m; memset(isPrime, 1, sizeof(isPrime)); isPrime[0] = isPrime[1] = false; m = sqrt(maxS) + 0.5; for(int i=2; i<m; i++) { if(isPrime[i]) { for(int j=i*i; j<maxS; j+=i) isPrime[j] = false; } } cin >> n; while(n) { flag = false; if(isPrime[n]) { cout << n << " is normal." << endl; cin >> n; continue; } for(int i=2; i<n; i++) if(PowMod(i, n, n) != i) { flag = true; break; } if(!flag) cout << "The number " << n << " is a Carmichael number." << endl; else cout << n << " is normal." << endl; cin >> n; } return 0; }
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原文地址:http://www.cnblogs.com/ZengWangli/p/5835801.html