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原题如下：
The string "PAYPALISHIRING" is written in a zigzag pattern on a given number of rows like this: (you may want to display this pattern in a fixed font for better legibility)
P A H N A P L S I I G Y I R
And then read line by line: "PAHNAPLSIIGYIR"
Write the code that will take a string and make this conversion given a number of rows:
string convert(string text, int nRows);
convert("PAYPALISHIRING", 3) should return "PAHNAPLSIIGYIR".
实现思路比较简单直白，直接上代码吧：
1 public String convert(String s, int nRows) { 2 int len = s.length(); 3 if(nRows >= len || nRows == 1){ 4 return s; 5 } 6 StringBuilder sb = new StringBuilder(); 7 for(int i =0; i< nRows; i++){ 8 int n = i; 9 while(n<len){ 10 sb.append(s.charAt(n)); 11 if(i!=0 && i!= nRows-1){ 12 n+=(nRows-i-1)<<1; 13 if(n<len){ 14 sb.append(s.charAt(n)); 15 n+=i<<1; 16 } 17 }else{ 18 n+=(nRows-1)<<1; 19 } 20 } 21 } 22 return sb.toString(); 23 }
LeetCode 6 - ZigZag Conversion
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原文地址：http://www.cnblogs.com/pkufork/p/ds_leetcode_6.html
