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BestCoder Round #4 1002

时间:2014-08-10 23:56:20      阅读:275      评论:0      收藏:0      [点我收藏+]

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这题真是丧心病狂,引来今天的hack狂潮~

 

Miaomiao‘s Geometry

Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/65536 K (Java/Others) Total Submission(s): 10    Accepted Submission(s): 3

Problem Description
There are N point on X-axis . Miaomiao would like to cover them ALL by using segments with same length.
There are 2 limits:
1.A point is convered if there is a segments T , the point is the left end or the right end of T. 2.The length of the intersection of any two segments equals zero.
For example , point 2 is convered by [2 , 4] and not convered by [1 , 3]. [1 , 2] and [2 , 3] are legal segments , [1 , 2] and [3 , 4] are legal segments , but [1 , 3] and [2 , 4] are not (the length of intersection doesn‘t equals zero), [1 , 3] and [3 , 4] are not(not the same length).
Miaomiao wants to maximum the length of segements , please tell her the maximum length of segments.
For your information , the point can‘t coincidently at the same position.
 
Input
There are several test cases. There is a number T ( T <= 50 ) on the first line which shows the number of test cases. For each test cases , there is a number N ( 3 <= N <= 50 ) on the first line. On the second line , there are N integers Ai (-1e9 <= Ai <= 1e9) shows the position of each point.
 
Output
For each test cases , output a real number shows the answser. Please output three digit after the decimal point.
 
Sample Input
3 3 1 2 3 3 1 2 4 4 1 9 100 10
 
Sample Output
1.000 2.000 8.000
Hint
For the first sample , a legal answer is [1,2] [2,3] so the length is 1. For the second sample , a legal answer is [-1,1] [2,4] so the answer is 2. For the thired sample , a legal answer is [-7,1] , [1,9] , [10,18] , [100,108] so the answer is 8.
 
正解还在讨论中,不过有多种,,,被hack掉的。。

BestCoder Round #4 1002,布布扣,bubuko.com

BestCoder Round #4 1002

标签:des   style   color   java   os   io   strong   for   

原文地址:http://www.cnblogs.com/njczy2010/p/3903396.html

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