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1 // 圆内,求离圆心最远的整数点 hiho一下第111周 Farthest Point 2 // 思路:直接暴力绝对T 3 // 先确定x范围,每个x范围内,离圆心最远的点一定是y轴两端的点。枚举x的范围,再比较y 4 // O(n) 5 6 #include <bits/stdc++.h> 7 using namespace std; 8 #define LL long long 9 const double inf = 123456789012345.0; 10 const LL MOD =100000000LL; 11 const int N =1e7+10; 12 #define clc(a,b) memset(a,b,sizeof(a)) 13 const double eps = 1e-7; 14 void fre() {freopen("in.txt","r",stdin);} 15 void freout() {freopen("out.txt","w",stdout);} 16 inline int read() {int x=0,f=1;char ch=getchar();while(ch>‘9‘||ch<‘0‘) {if(ch==‘-‘) f=-1; ch=getchar();}while(ch>=‘0‘&&ch<=‘9‘) {x=x*10+ch-‘0‘;ch=getchar();}return x*f;} 17 18 double dis(double a,double b,double c,double d){ 19 return (a-c)*(a-c)+(b-d)*(b-d); 20 } 21 int main(){ 22 double x,y,r; 23 double len=-1; 24 int ans_y,ans_x; 25 scanf("%lf%lf%lf",&x,&y,&r); 26 for(double i=floor(x+r);i>=ceil(x-r);i--){ 27 double d=(double)sqrt(r*r-(i-x)*(i-x)); 28 double y1=floor(d+y),y2=ceil(y-d); 29 if(dis(x,y,i,y1)>len){ 30 len=dis(x,y,i,y1); 31 ans_x=i,ans_y=y1; 32 } 33 if(dis(x,y,i,y2)>len){ 34 len=dis(x,y,i,y2); 35 ans_x=i,ans_y=y2; 36 } 37 } 38 printf("%d %d\n",ans_x,ans_y); 39 return 0; 40 }
圆内,求离圆心最远的整数点 hiho一下第111周 Farthest Point
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原文地址:http://www.cnblogs.com/ITUPC/p/5847610.html