标签:des style color java os io strong for
4 0 3 2 1 2 1 3
4 2HintCase 2: First prove set 2 is a subset of set 1 and then prove set 3 is a subset of set 1.
#include"stdio.h"
#include"string.h"
#include"queue"
#include"vector"
#include"algorithm"
using namespace std;
#define N 20005
#define M 50005
#define min(a,b) (a<b?a:b)
const int inf=1000000;
struct node
{
int u,v,next;
}e[M];
int t,bcnt,index,stop,ans;
int head[N],dfn[N],low[N],stap[N],mark[N],be[N];
int indeg[N],out[N];
void add(int u,int v)
{
e[t].u=u;
e[t].v=v;
e[t].next=head[u];
head[u]=t++;
}
void tarjan(int u)
{
int i,v;
dfn[u]=low[u]=++index;
stap[++stop]=u;
mark[u]=1;
for(i=head[u];i!=-1;i=e[i].next)
{
v=e[i].v;
if(!dfn[v])
{
tarjan(v);
low[u]=min(low[u],low[v]);
}
else if(mark[v])
low[u]=min(low[u],dfn[v]);
}
if(low[u]==dfn[u])
{
bcnt++;
do
{
v=stap[stop--];
mark[v]=0;
be[v]=bcnt;
}
while(u!=v);
ans++;
}
}
void solve(int n)
{
int i;
memset(dfn,0,sizeof(dfn));
index=stop=bcnt=0;
for(i=1;i<=n;i++)
{
if(!dfn[i])
tarjan(i);
}
}
void work(int n)
{
int i,j,u,v,t1,t2;
memset(indeg,0,sizeof(indeg));
memset(out,0,sizeof(out));
for(i=1;i<=n;i++)
{
u=be[i];
for(j=head[i];j!=-1;j=e[j].next)
{
v=be[e[j].v];
if(u!=v)
{
indeg[v]++;
out[u]++;
}
}
}
t1=t2=0;
for(i=1;i<=bcnt;i++)
{
if(indeg[i]==0)
t1++;
if(out[i]==0)
t2++;
}
printf("%d\n",t1>t2?t1:t2);
}
int main()
{
int n,m,u,v;
while(scanf("%d%d",&n,&m)!=-1)
{
t=0;
memset(head,-1,sizeof(head));
while(m--)
{
scanf("%d%d",&u,&v);
add(u,v);
}
ans=0;
solve(n);
// printf("%d\n",ans);
if(ans==1)
printf("0\n");
else
work(n);
}
return 0;
}hdu 3836 Equivalent Sets(强连通分量--加边),布布扣,bubuko.com
hdu 3836 Equivalent Sets(强连通分量--加边)
标签:des style color java os io strong for
原文地址:http://blog.csdn.net/u011721440/article/details/38490781