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链接:http://vjudge.net/problem/35575
分析:dfs暴力。
1 #include <cstdio> 2 #include <cstring> 3 4 const int r = 7; 5 const int c = 8; 6 const int m = 30; 7 const int dir[2][2] = { 8 {0, 1}, 9 {1, 0}, 10 }; 11 12 int map[r][c], id[r][r], checked[m], vis[r][c], ans; 13 14 void build() { 15 int num = 1; 16 for (int i = 0; i < r; i++) 17 for (int j = i; j < r; j++) 18 id[i][j] = id[j][i] = num++; 19 } 20 21 bool init() { 22 ans = 0; 23 memset(checked, 0, sizeof(checked)); 24 memset(vis, 0, sizeof(vis)); 25 for (int i = 0; i < r; i++) 26 for (int j = 0; j < c; j++) 27 if (scanf("%d", &map[i][j]) != 1) return false; 28 return true; 29 } 30 31 void print() { 32 for (int i = 0; i < r; i++) { 33 for (int j = 0; j < c; j++) printf("%4d", vis[i][j]); 34 printf("\n"); 35 } 36 printf("\n"); 37 } 38 39 void dfs(int x, int y, int cnt) { 40 if (cnt == 28) { 41 ans++; 42 print(); 43 return; 44 } 45 if (y == c) { x++; y = 0; } 46 47 if (vis[x][y]) dfs(x, y + 1, cnt); 48 else { 49 for (int i = 0; i < 2; i++) { 50 int nx = x + dir[i][0], ny = y + dir[i][1]; 51 if (nx >= r || ny >= c || vis[nx][ny]) continue; 52 int n = id[map[x][y]][map[nx][ny]]; 53 if (checked[n]) continue; 54 vis[x][y] = vis[nx][ny] = n; checked[n] = 1; 55 dfs(x, y + 1, cnt + 1); 56 vis[x][y] = vis[nx][ny] = 0; checked[n] = 0; 57 } 58 } 59 } 60 61 int main() { 62 build(); 63 int kase = 0; 64 while (init()) { 65 if (kase) printf("\n\n\n"); 66 printf("Layout #%d:\n\n", ++kase); 67 for (int i = 0; i < r; i++) { 68 for (int j = 0; j < c; j++) 69 printf("%4d", map[i][j]); 70 printf("\n"); 71 } 72 printf("\nMaps resulting from layout #%d are:\n\n", kase); 73 dfs(0, 0, 0); 74 printf("There are %d solution(s) for layout #%d.\n", ans, kase); 75 } 76 return 0; 77 }
UVa211 The Domino Effect (DFS)
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原文地址:http://www.cnblogs.com/XieWeida/p/5860262.html