思想:1、利用全排列函数next_permutation()求出所有可能的序列
2、从中选出所有正确的序列
#include <iostream> #include <stack> #include <vector> #include <algorithm> using namespace std; //判断序列是否是合法的出栈序列 bool IsPopOrder(const int* pPush,const int* pPop,int n) { if (pPush == NULL || pPop == NULL || n == 0) return false; int i = 0; int j = 0; stack<int> s; while (i < n){ if (!s.empty() && pPop[j] == s.top()){ s.pop(); ++j; } else{ s.push(pPush[i++]); } } while (j<n && pPop[j] == s.top()){ s.pop(); ++j; } if (j == n ) return true; else return false; } int main() { vector<int> vPush; vector<int> vPop; int n = 0; cin >> n; int tmp = 0; for (int i = 0; i < n; ++i){ cin >> tmp; vPush.push_back(tmp); vPop.push_back(tmp); } sort(vPush.begin(),vPush.end()); int count = 0; //循环判断所有的序列是否合法 while(1){ int* pPush = &vPush[0]; int* pPop = &vPop[0]; count += IsPopOrder(pPush, pPop, n); if (next_permutation(vPop.begin(), vPop.end()) == false) break; } cout << count << endl; system("pause"); return 0; }
《完》
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原文地址:http://lingdandan.blog.51cto.com/10697032/1851430