给你六种面额1 5 10 20 50 100元的纸币假设每种币值的数量足够多

 1 function fn (all) {
 2     const arr = [1, 5, 10, 20, 50, 100],
 3         len = arr.length,
 4         res = [];
 5     for (let i = 0; i <= len; i++) {
 6         res[i] = [];
 7         res[i][0] = 1;
 8     }
 9     for (let j = 1; j <= all; j++) {
10         res[0][j] = 0;
11     }
12     for (let i = 1; i <= len; i++) {
13         for (let j = 1; j <= all; j++) {
14             res[i][j] = 0;
15             for (let k = 0; k <= j / arr[i - 1]; k++) {
16                 res[i][j] += res[i - 1][j - k * arr[i - 1]];
17             }
18         }
19     }
20     return res[len][all];
21 }