标签:
Given an array containing n distinct numbers taken from 0, 1, 2, ..., n
, find the one that is missing from the array.
For example,
Given nums = [0, 1, 3]
return 2
.
Note:
Your algorithm should run in linear runtime complexity. Could you implement it using only constant extra space complexity?
1 class Solution { 2 public: 3 int missingNumber(vector<int>& nums) { 4 int number = 0; 5 for(int i = 0; i <= nums.size(); i++) 6 number ^= i; 7 for(auto n : nums) 8 number ^= n; 9 10 return number; 11 } 12 };
标签:
原文地址:http://www.cnblogs.com/sankexin/p/5863970.html