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Given a linked list, determine if it has a cycle in it.
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Can you solve it without using extra space?
1 /** 2 * Definition for singly-linked list. 3 * struct ListNode { 4 * int val; 5 * ListNode *next; 6 * ListNode(int x) : val(x), next(NULL) {} 7 * }; 8 */ 9 class Solution { 10 public: 11 bool hasCycle(ListNode *head) { 12 if(head == NULL || head->next == NULL){ 13 return false; 14 } 15 16 ListNode* fast = head; 17 ListNode* slow = head; 18 19 while(fast->next != NULL && fast->next->next != NULL) 20 { 21 fast = fast->next->next; 22 slow = slow->next; 23 if(fast == slow){ 24 return true; 25 } 26 } 27 return false; 28 } 29 };
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原文地址:http://www.cnblogs.com/sankexin/p/5863997.html