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Given a binary tree, imagine yourself standing on the right side of it, return the values of the nodes you can see ordered from top to bottom.
For example:
Given the following binary tree,
1 <--- / 2 3 <--- \ 5 4 <---
You should return [1, 3, 4].
Credits:
Special thanks to @amrsaqr for adding this problem and creating all test cases.
Solution:
/** * Definition for a binary tree node. * public class TreeNode { * int val; * TreeNode left; * TreeNode right; * TreeNode(int x) { val = x; } * } */ public class Solution { public List<Integer> rightSideView(TreeNode root) { List<Integer> resList = new LinkedList<Integer>(); rightSideViewRecur(root,resList,1); return resList; } public void rightSideViewRecur(TreeNode curNode, List<Integer> resList, int depth){ if (curNode==null){ return; } if (resList.size()<depth){ resList.add(curNode.val); } rightSideViewRecur(curNode.right,resList,depth+1); rightSideViewRecur(curNode.left,resList,depth+1); } }
LeetCode-Binary Tree Right Side View
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原文地址：http://www.cnblogs.com/lishiblog/p/5867086.html
