198. House Robber

标签：

You are a professional robber planning to rob houses along a street. Each house has a certain amount of money stashed, the only constraint stopping you from robbing each of them is that adjacent houses have security system connected and it will automatically contact the police if two adjacent houses were broken into on the same night.

Given a list of non-negative integers representing the amount of money of each house, determine the maximum amount of money you can rob tonightwithout alerting the police.

非常经典的小偷问题。怎么偷：如果偷现在的这家，那么总钱数就是现在的加上之前之前的。如果不偷，那么总钱数就是之前这家。比较两者哪个大来决定偷或者不偷。

public class Solution {
    public int rob(int[] nums) {
        if(nums.length==0)
        {
            return 0;
        }
        int[] dp=new int[nums.length+1];
        dp[0]=0;
        dp[1]=nums[0];
        for(int i=2;i<=nums.length;i++)
        {
            dp[i]=Math.max(dp[i-2]+nums[i-1],dp[i-1]);
        }
        return dp[nums.length];
    }
}

198. House Robber

标签：

原文地址：http://www.cnblogs.com/Machelsky/p/5874633.html