标签:acm
const int MAXN = 1100000; struct Seg { int l, r; bool operator< (const Seg& rhs)const { return r - l < rhs.r - rhs.l; } } ipt[MAXN]; VI split; int ans[MAXN], q[MAXN]; set<int> st; set<int>::iterator it; int main() { int n, m; while (~RI(n)) { split.clear(); CLR(ans, -1); FE(i, 1, n) { RII(ipt[i].l, ipt[i].r); split.push_back(ipt[i].l); split.push_back(ipt[i].r); split.push_back(ipt[i].l - 1); split.push_back(ipt[i].r + 1); } RI(m); REP(i, m) { RI(q[i]); split.push_back(q[i]); } sort(all(split)); split.erase(unique(all(split)), split.end()); FE(i, 0, split.size()) st.insert(i); st.insert(INF); FED(i, n, 1) { int l = lower_bound(all(split), ipt[i].l) - split.begin(); int r = lower_bound(all(split), ipt[i].r) - split.begin(); it = st.lower_bound(l); while (*it <= r) { ans[*it] = i; st.erase(it++); } } REP(i, m) { int id = lower_bound(all(split), q[i]) - split.begin(); WI(ans[id]); } } return 0; }
Nested Segments,布布扣,bubuko.com
标签:acm
原文地址:http://blog.csdn.net/wty__/article/details/38497043