利用block完成回调,小demo一个。闲话少说,直接上代码了!O(∩_∩)O~
TestObject.h
#import <Foundation/Foundation.h> typedef void (^FinishBlock)(NSString *backStr); @interface TestObject : NSObject //能进行回调的方法 - (void)playSomeTime:(FinishBlock)block; @end
TestObject.m
#import "TestObject.h" @implementation TestObject - (void)playSomeTime:(FinishBlock)block{ for (int i = 0; i< 5000; i++) { NSLog(@"i===%d",i); } block(@"被回调的字符串O(∩_∩)O~"); } @end
ViewController.h
#import <UIKit/UIKit.h> @interface ViewController : UIViewController @end
ViewController.m
#import "ViewController.h" #import "TestObject.h" @interface ViewController () @end @implementation ViewController - (void)viewDidLoad { [super viewDidLoad]; TestObject *obj = [[TestObject alloc] init]; [obj playSomeTime:^(NSString *backStr){ NSLog(@"回调完成,被返回的结果===%@",backStr); }]; NSLog(@"这是同步操作,需要等待回调完成"); } - (void)didReceiveMemoryWarning { [super didReceiveMemoryWarning]; } @end
利用block完成回调,小demo一个,布布扣,bubuko.com
原文地址:http://blog.csdn.net/u011439689/article/details/38496715