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LeetCode 100. Same Tree

时间:2016-09-16 21:03:29      阅读:153      评论:0      收藏:0      [点我收藏+]

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Given two binary trees, write a function to check if they are equal or not.

Two binary trees are considered equal if they are structurally identical and the nodes have the same value.

 

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这个题目比较简单,只需要比较节点的值以及子树是否相等即可

 

/**
 * Definition for a binary tree node.
 * struct TreeNode {
 *     int val;
 *     TreeNode *left;
 *     TreeNode *right;
 *     TreeNode(int x) : val(x), left(NULL), right(NULL) {}
 * };
 */
class Solution {
public:
    bool isSameTree(TreeNode* p, TreeNode* q) {
        if(p==NULL&&q==NULL)return true;
        if(p==NULL||q==NULL)return false;
        return p->val==q->val&&isSameTree(p->left,q->left)&&isSameTree(p->right,q->right);
    }
};

 

LeetCode 100. Same Tree

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原文地址:http://www.cnblogs.com/csudanli/p/5877097.html

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