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--orderid 1:1028 10:10257 20:10267 30:10277 --查询第20-30条 select top 10 * from Orders where OrderID> (select max(OrderID) from (select top 20 OrderID from Orders order by OrderID ASC ) t0 ) order by OrderID ASC
原文链接：http://www.cnblogs.com/bluedoctor/archive/2011/11/01/2232297.html
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原文地址：http://www.cnblogs.com/wuhailong/p/5880737.html
