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Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)
Total Submission(s): 11715 Accepted Submission(s): 5661
1 /****************************** 2 code by drizzle 3 blog: www.cnblogs.com/hsd-/ 4 ^ ^ ^ ^ 5 O O 6 ******************************/ 7 //#include<bits/stdc++.h> 8 #include<iostream> 9 #include<cstring> 10 #include<cmath> 11 #include<cstdio> 12 #define ll long long 13 #define mod 1000000007 14 #define PI acos(-1.0) 15 using namespace std; 16 int main() 17 { 18 int a[105][105]; 19 int b[105]; 20 int n; 21 while(scanf("%d",&n)!=EOF) 22 { 23 for(int i=1;i<=n;i++) 24 { 25 for(int j=1;j<=n;j++) 26 scanf("%d",&a[i][j]); 27 } 28 int maxn=-100000; 29 for(int i=1;i<=n;i++) 30 { 31 memset(b,0,sizeof(b)); 32 for(int j=i;j<=n;j++) 33 { 34 int sum=0; 35 for(int k=1;k<=n;k++) 36 { 37 b[k]+=a[j][k]; 38 sum+=b[k]; 39 if(sum<0) sum=b[k]; 40 if(sum>maxn) maxn=sum; 41 } 42 } 43 } 44 printf("%d\n",maxn); 45 } 46 return 0; 47 }
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原文地址:http://www.cnblogs.com/hsd-/p/5891082.html