LeetCode 383. Ransom Note

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?Given? an ?arbitrary? ransom? note? string ?and ?another ?string ?containing ?letters from? all ?the ?magazines,? write ?a ?function ?that ?will ?return ?true ?if ?the ?ransom ? note ?can ?be ?constructed ?from ?the ?magazines ; ?otherwise, ?it ?will ?return ?false. ??

Each ?letter? in? the? magazine ?string ?can? only ?be? used ?once? in? your ?ransom? note.

Note:
You may assume that both strings contain only lowercase letters.

canConstruct("a", "b") -> false
canConstruct("aa", "ab") -> false
canConstruct("aa", "aab") -> true

class Solution {
public:
    bool canConstruct(string ransomNote, string magazine) {
        map<char, int> map;
        for (auto &e : ransomNote)
        {
            ++map[e];
        }
        for (auto &e : magazine)
        {
            if (map.find(e) != map.end())
            {
                if (--map[e] == 0)
                {
                    map.erase(e);
                }
            }
        }
        return !map.size();
    }
};

LeetCode 383. Ransom Note

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原文地址：http://www.cnblogs.com/csudanli/p/5891209.html