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1 class Solution { 2 public: 3 bool search(vector<int>& nums, int target) { 4 if (nums.size() == 0) return false; 5 else { 6 int first = 0, last = nums.size() - 1; 7 while (first <= last) { 8 int mid = first + (last - first) / 2; 9 if (nums[mid] == target) return true; 10 else { 11 if (nums[first] < nums[mid]) { 12 if (nums[first] <= target && target < nums[mid]) last = mid - 1; 13 else first = mid + 1; 14 } 15 else if (nums[first] > nums[mid]) { 16 if (nums[mid] < target && target <= nums[last]) first = mid + 1; 17 else last = mid - 1; 18 } 19 else { 20 ++first; 21 } 22 } 23 } 24 return false; 25 } 26 } 27 };
081. Search in Rotated Sorted Array II
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原文地址:http://www.cnblogs.com/shadowwalker9/p/5899818.html