term does not evaluate to a function taking N arguments
A call is made to a function through an expression.The expression does not evaluate to a pointer to a function that takes the specified number of arguments.
In this example, the code attempts to call non-functions as functions.The following sample generates C2064:
// C2064.cpp
int i, j;
char* p;
void func() {
j = i(); // C2064, i is not a function
p(); // C2064, p doesn‘t point to a function
}
You must call pointers to non-static member functions from the context of an object instance.The following sample generates C2064, and shows how to fix it:
// C2064b.cpp
struct C {
void func1() {}
void func2() {}
};
typedef void (C::*pFunc)();
int main() {
C c;
pFunc funcArray[2] = { &C::func1, &C::func2 };
(funcArray[0])(); // C2064
(c.*funcArray[0])(); // OK - function called in instance context
}
Within a class, member function pointers must also indicate the calling object context.The following sample generates C2064 and shows how to fix it:
// C2064d.cpp
// Compile by using: cl /c /W4 C2064d.cpp
struct C {
typedef void (C::*pFunc)();
pFunc funcArray[2];
void func1() {}
void func2() {}
C() {
funcArray[0] = &C::func1;
funcArray[1] = &C::func2;
}
void func3() {
(funcArray[0])(); // C2064
(this->*funcArray[0])(); // OK - called in this instance context
}
};
