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题意:给定一个序列,让你用最少的操作把它变成交替的,操作有两种,任意交换两种,再就是把一种变成另一种。
析:贪心,策略是分别从br开始和rb开始然后取最优,先交换,交换是最优的,不行再变色。
代码如下:
#pragma comment(linker, "/STACK:1024000000,1024000000")
#include <cstdio>
#include <string>
#include <cstdlib>
#include <cmath>
#include <iostream>
#include <cstring>
#include <set>
#include <queue>
#include <algorithm>
#include <vector>
#include <map>
#include <cctype>
#include <cmath>
#include <stack>
#include <tr1/unordered_map>
#define freopenr freopen("in.txt", "r", stdin)
#define freopenw freopen("out.txt", "w", stdout)
using namespace std;
using namespace std :: tr1;
typedef long long LL;
typedef pair<int, int> P;
const int INF = 0x3f3f3f3f;
const double inf = 0x3f3f3f3f3f3f;
const LL LNF = 0x3f3f3f3f3f3f;
const double PI = acos(-1.0);
const double eps = 1e-8;
const int maxn = 1e5 + 5;
const int mod = 1e9 + 7;
const int N = 1e6 + 5;
const int dr[] = {-1, 0, 1, 0, 1, 1, -1, -1};
const int dc[] = {0, 1, 0, -1, 1, -1, 1, -1};
const char *Hex[] = {"0000", "0001", "0010", "0011", "0100", "0101", "0110", "0111", "1000", "1001", "1010", "1011", "1100", "1101", "1110", "1111"};
inline LL gcd(LL a, LL b){ return b == 0 ? a : gcd(b, a%b); }
int n, m;
const int mon[] = {0, 31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31};
const int monn[] = {0, 31, 29, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31};
inline int Min(int a, int b){ return a < b ? a : b; }
inline int Max(int a, int b){ return a > b ? a : b; }
inline LL Min(LL a, LL b){ return a < b ? a : b; }
inline LL Max(LL a, LL b){ return a > b ? a : b; }
inline bool is_in(int r, int c){
return r >= 0 && r < n && c >= 0 && c < m;
}
char s[maxn];
int solve(char ch, char sh){
int cntr = 0, cntb = 0, ans = 0;
for(int i = 0; i < n; ++i){
if(i & 1){
if(s[i] == ch) continue;
if(s[i] == sh){
if(cntr) --cntr;
else ++ans, ++cntb;
}
}
else{
if(s[i] == sh) continue;
if(s[i] == ch){
if(cntb) --cntb;
else ++ans, ++cntr;
}
}
}
return ans;
}
int main(){
while(scanf("%d", &n) == 1){
scanf("%s", s);
int ans = Min(solve(‘b‘, ‘r‘), solve(‘r‘, ‘b‘));
printf("%d\n", ans);
}
return 0;
}
CodeForces 719B Anatoly and Cockroaches (水题贪心)
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原文地址:http://www.cnblogs.com/dwtfukgv/p/5904399.html