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Given n non-negative integers a1, a2, ..., an, where each represents a point at coordinate (i, ai). n vertical lines are drawn such that the two endpoints of line i is at (i, ai) and (i, 0). Find two lines, which together with x-axis forms a container, such that the container contains the most water.
Note: You may not slant the container.
这道题里面,一开始从左右两边开始,这个case下宽度是最大的,那之后出现比它大的情况只有两条边中至少一边更长。一种思路是先从左边开始,如果左边比右边小,那么向左挪一位,继续比较。当左边比右边大的情况下,修正结果。然后从右边开始挪,因为此时左边的边是更大的,只有右边比左边还大才可能比之前的contains更多水。
public int MaxArea(int[] height) { int left = 0; int right = height.Count()-1; int res =Math.Min(height[right],height[left])*(right - left); while(left<right) { res =Math.Max(res,Math.Min(height[right],height[left])*(right - left)); if(height[left]>= height[right]) { right--; } else { left++; } } return res; }
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原文地址:http://www.cnblogs.com/renyualbert/p/5907685.html