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描述
Ignatius was born in a leap year, so he want to know when he could hold his birthday party. Can you tell him?
Given a positive integers Y which indicate the start year, and a positive integer N, your task is to tell the Nth leap year from year Y.
Note: if year Y is a leap year, then the 1st leap year is year Y.
输入
The input contains several test cases. The first line of the input is a single integer T which is the number of test cases. T test cases follow.
Each test case contains two positive integers Y and N(1<=N<=10000).
输出
For each test case, you should output the Nth leap year from year Y.
样例输入
3
2005 25
1855 12
2004 10000
样例输出
2108
1904
43236
code :
#include<iostream>
#include<cstdio>
#include<cstring>
#include<algorithm>
using namespace std;
bool isLoop(int y){
if((y%4==0 && y%100!=0) || y%400==0){
return true;
}
return false;
}
int main()
{
int t, y, n;
cin>>t;
while(t--){
cin>>y>>n;
while(n){
if(isLoop(y)){
n--;
}
y++;
}
cout<<y-1<<endl;
}
return 0;
}
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原文地址：http://www.cnblogs.com/lzeffort/p/5925519.html
