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[LeetCode] 17. Letter Combinations of a Phone Number

时间:2016-10-02 00:20:22      阅读:192      评论:0      收藏:0      [点我收藏+]

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Given a digit string, return all possible letter combinations that the number could represent.

A mapping of digit to letters (just like on the telephone buttons) is given below.

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Input:Digit string "23"
Output: ["ad", "ae", "af", "bd", "be", "bf", "cd", "ce", "cf"].

Note:
Although the above answer is in lexicographical order, your answer could be in any order you want.

 1 class Solution {
 2     unordered_map<char, vector<string>> ht  = {
 3              {0, {" "}}, {1, {""}}, {2, {"a", "b", "c"}}, {3, {"d", "e", "f"}},
 4              {4, {"g", "h", "i"}}, {5, {"j", "k", "l"}}, {6, {"m", "n", "o"}},
 5              {7, {"p", "q", "r", "s"}}, {8, {"t", "u", "v"}}, {9, {"w", "x", "y", "z"}},
 6     };       
 7 public:
 8     vector<string> letterCombinations(string digits) {
 9         vector<string> ret;
10         int n = digits.size();
11         
12         if (n == 0) return ret;
13     
14         if (n == 1) return ht[digits[0]];
15        
16         vector<string> prev = letterCombinations(digits.substr(0, n - 1));
17 
18         for (auto s : prev){
19             for (int i = 0; i < ht[digits[n-1]].size(); i++)
20             ret.push_back(s+ht[digits[n-1]][i]);
21         }
22         
23         return ret;
24     }
25 };

 

[LeetCode] 17. Letter Combinations of a Phone Number

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原文地址:http://www.cnblogs.com/amadis/p/5926503.html

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