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Given a sorted linked list, delete all nodes that have duplicate numbers, leaving only distinct numbers from the original list.
For example,
Given 1->2->3->3->4->4->5
, return 1->2->5
.
Given 1->1->1->2->3
, return 2->3
.
/** * Definition for singly-linked list. * struct ListNode { * int val; * ListNode *next; * ListNode(int x) : val(x), next(NULL) {} * }; */ class Solution{ public: ListNode* deleteDuplicates(ListNode* head){ if(!head || !head->next) return head; ListNode* newHead = new ListNode(-1); newHead->next = head; ListNode* pre = newHead; ListNode* cur = head; bool duplicated = false;// if has duplicates while(cur->next){ if(cur->val == cur->next->val){ cur = cur->next; duplicated = true; }else{ if(duplicated){ while(pre->next != cur->next){ ListNode* tmp = pre->next; pre->next = pre->next->next; delete tmp; } // pre->next = cur->next; duplicated = false; }else{ pre->next = cur; pre = cur; } cur = cur->next; } } if(duplicated){ pre->next = nullptr; } return newHead->next; } };
Remove Duplicates from Sorted List II
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原文地址:http://www.cnblogs.com/wxquare/p/5928085.html