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题解:
set
此题关键是理解题意
题意链接:http://blog.csdn.net/luyuncheng/article/details/8053971
代码:
#include<iostream> #include<cstring> #include<cstdio> #include<algorithm> #include<cmath> #include<map> #include<set> #include<vector> using namespace std; using namespace std; #define pb push_back #define mp make_pair #define se second #define fs first #define ll long long #define MS(x,y) memset(x,y,sizeof(x)) #define MC(x,y) memcpy(x,y,sizeof(x)) #define ls o<<1 #define rs o<<1|1 #define SZ(x) ((int)(x).size()) #define FOR(it,c) for(__typeof((c).begin()) it=(c).begin();it!=(c).end();it++) typedef pair<int,int> P; const double eps=1e-9; const int maxn=100100; const int N=1e9; const int mod=1e9+7; ll read() { ll x=0,f=1;char ch=getchar(); while(ch<‘0‘||ch>‘9‘){if(ch==‘-‘)f=-1;ch=getchar();} while(ch>=‘0‘&&ch<=‘9‘){x=x*10+ch-‘0‘;ch=getchar();} return x*f; } //----------------------------------------------------------------------------- set<int> s; int n,a; set<int>::iterator it; int main(){ int Kase=1; while(~scanf("%d",&n)){ s.clear(); int num=0; for(int i=1;i<=n;i++){ scanf("%d",&a); if(a==0) s.clear(); else{ if(!s.count(a)){ s.insert(a); num++; } for(it=s.upper_bound(a);it!=s.end();)s.erase(it++); } } printf("Case %d: %d\n",Kase++,num); } return 0; }
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原文地址:http://www.cnblogs.com/byene/p/5931577.html