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题目链接:
Time Limit: 7000/3500 MS (Java/Others) Memory Limit: 65536/65536 K (Java/Others)
Total Submission(s): 207 Accepted Submission(s): 41
#pragma comment(linker, "/STACK:102400000,102400000")
#include <iostream>
#include <cstdio>
#include <cstring>
#include <algorithm>
#include <cmath>
#include <bits/stdc++.h>
#include <stack>
#include <map>
using namespace std;
#define For(i,j,n) for(int i=j;i<=n;i++)
#define mst(ss,b) memset(ss,b,sizeof(ss));
typedef long long LL;
typedef unsigned long long ULL;
template<class T> void read(T&num) {
char CH; bool F=false;
for(CH=getchar();CH<‘0‘||CH>‘9‘;F= CH==‘-‘,CH=getchar());
for(num=0;CH>=‘0‘&&CH<=‘9‘;num=num*10+CH-‘0‘,CH=getchar());
F && (num=-num);
}
int stk[70], tp;
template<class T> inline void print(T p) {
if(!p) { puts("0"); return; }
while(p) stk[++ tp] = p%10, p/=10;
while(tp) putchar(stk[tp--] + ‘0‘);
putchar(‘\n‘);
}
const LL mod=1e9+7;
const double PI=acos(-1.0);
const int inf=1e9;
const int N=2e5+4;
const int maxn=2e5+20;
const double eps=1e-12;
int n,m,a[2*maxn];
char s[20];
deque<int>qu;
int flag,l,r;
void POP()
{
if(flag)
{
if(a[r]==0)qu.pop_back();
r--;
}
else
{
if(a[l]==0)qu.pop_front();
l++;
}
}
void PUSH(int x)
{
if(flag)
{
a[++r]=x;
if(x==0)qu.push_back(r);
}
else
{
a[--l]=x;
if(x==0)qu.push_front(l);
}
}
void Rev(){flag^=1;}
void query()
{
if(qu.empty())
{
if(r<l){printf("Invalid.\n");return ;}
int num=r-l+1;
if(num&1)printf("1\n");
else printf("0\n");
}
else
{
if(flag)
{
int fr=qu.front();
int num=fr-l;
if(num&1)
{
if(fr==r)printf("1\n");
else printf("0\n");
}
else
{
if(fr==r)printf("0\n");
else printf("1\n");
}
}
else
{
int fr=qu.back();
int num=r-fr;
if(num&1)
{
if(fr==l)printf("1\n");
else printf("0\n");
}
else
{
if(fr==l)printf("0\n");
else printf("1\n");
}
}
}
return ;
}
inline void Init()
{
flag=1;l=N;r=N-1;
while(!qu.empty())qu.pop_back();
}
int main()
{
int t,Case=0;
read(t);
while(t--)
{
Init();
printf("Case #%d:\n",++Case);
read(n);
for(int i=1;i<=n;i++)
{
scanf("%s",s);
if(s[0]==‘P‘)
{
if(s[1]==‘U‘)
{
int x;
scanf("%d",&x);
PUSH(x);
}
else POP();
}
else if(s[0]==‘R‘)Rev();
else query();
}
}
return 0;
}
hdu-5929 Basic Data Structure(双端队列+模拟)
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原文地址:http://www.cnblogs.com/zhangchengc919/p/5934945.html