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Time Limit: 4000/2000 MS (Java/Others) Memory Limit: 131070/65535 K (Java/Others)
Total Submission(s): 35179 Accepted Submission(s): 13183
字典树。
交G++不停MLE是什么鬼,交C++才AC。。。
1 //2016.10.7 2 #include <iostream> 3 #include <cstdio> 4 #include <cstdlib> 5 #include <cstring> 6 7 using namespace std; 8 9 struct node//26叉树,num为到该节点截止的前缀有多少个 10 { 11 node* ch[26]; 12 int num; 13 node(){ 14 num = 0; 15 for(int i = 0; i < 26; i++) 16 ch[i] = NULL; 17 } 18 }; 19 20 node *root = NULL; 21 char s[15]; 22 23 void Insert(char *s) 24 { 25 node* cur = root; 26 cur->num++; 27 for(int i = 0; i < strlen(s); i++) 28 { 29 int tmp = s[i]-‘a‘; 30 if(cur->ch[tmp] == NULL) 31 cur->ch[tmp] = new node; 32 cur = cur->ch[tmp]; 33 cur->num++; 34 } 35 } 36 37 int query(char *s) 38 { 39 node *cur = root; 40 for(int i = 0; i < strlen(s); i++) 41 { 42 int tmp = s[i]-‘a‘; 43 if(cur->ch[tmp] == NULL)return 0; 44 cur = cur->ch[tmp]; 45 } 46 return cur->num; 47 } 48 49 int main() 50 { 51 root = new node; 52 while(gets(s), strcmp(s, "")){ 53 Insert(s); 54 } 55 while(scanf("%s", s)!=EOF){ 56 printf("%d\n", query(s)); 57 } 58 59 return 0; 60 }
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原文地址:http://www.cnblogs.com/Penn000/p/5936223.html