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题目链接:
Time Limit: 9000/4500 MS (Java/Others) Memory Limit: 65536/65536 K (Java/Others)
Total Submission(s): 521 Accepted Submission(s): 148
#pragma comment(linker, "/STACK:102400000,102400000")
#include <iostream>
#include <cstdio>
#include <cstring>
#include <algorithm>
#include <cmath>
#include <bits/stdc++.h>
#include <stack>
#include <map>
using namespace std;
#define For(i,j,n) for(int i=j;i<=n;i++)
#define mst(ss,b) memset(ss,b,sizeof(ss));
typedef long long LL;
typedef unsigned long long ULL;
template<class T> void read(T&num) {
char CH; bool F=false;
for(CH=getchar();CH<‘0‘||CH>‘9‘;F= CH==‘-‘,CH=getchar());
for(num=0;CH>=‘0‘&&CH<=‘9‘;num=num*10+CH-‘0‘,CH=getchar());
F && (num=-num);
}
int stk[70], tp;
template<class T> inline void print(T p) {
if(!p) { puts("0"); return; }
while(p) stk[++ tp] = p%10, p/=10;
while(tp) putchar(stk[tp--] + ‘0‘);
putchar(‘\n‘);
}
const LL mod=1e9+7;
const double PI=acos(-1.0);
const int inf=1e9;
const int N=1e4+120;
const int maxn=1e5+20;
const double eps=1e-12;
int n,q,m,son[maxn],fa[maxn],dep[maxn],SON[maxn],temp[maxn];
vector<int>ve[maxn];
void dfs(int cur,int father,int deep)
{
int len=ve[cur].size();
dep[cur]=deep;
fa[cur]=father;
if(cur!=1)son[cur]=len-1;
else son[cur]=len;
for(int i=0;i<len;i++)
{
int x=ve[cur][i];
if(x==father)continue;
dfs(x,cur,deep+1);
}
}
int cmp(int x,int y){return dep[x]>dep[y];}
int main()
{
int t,Case=0;
read(t);
while(t--)
{
printf("Case #%d:\n",++Case);
for(int i=0;i<=n;i++)ve[i].clear();
read(n);read(q);
int u,v,x;
for(int i=1;i<n;i++)
{
read(u);read(v);
ve[u].push_back(v);
ve[v].push_back(u);
}
dfs(1,0,0);
while(q--)
{
read(m);
int ans=n-m;
for(int i=1;i<=m;i++)read(temp[i]),SON[temp[i]]=son[temp[i]];
sort(temp+1,temp+m+1,cmp);
for(int i=1;i<=m;i++)
{
if(SON[temp[i]]>=2)ans++;
else if(SON[temp[i]]==0)
{
int father=fa[temp[i]];
SON[father]--;
}
}
printf("%d\n",ans);
}
}
return 0;
}
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原文地址:http://www.cnblogs.com/zhangchengc919/p/5936526.html