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Given a binary tree, return the postorder traversal of its nodes‘ values.
For example:
Given binary tree {1,#,2,3}
,
1 2 / 3
return [3,2,1]
.
思路:后序遍历
/** * Definition for a binary tree node. * public class TreeNode { * int val; * TreeNode left; * TreeNode right; * TreeNode(int x) { val = x; } * } */ public class Solution { public List<Integer> postorderTraversal(TreeNode root) { List<Integer> res=new ArrayList<>(); if(root==null){ return res; } helper(res,root); return res; } public void helper(List<Integer> res,TreeNode root){ if(root==null){ return; } helper(res,root.left); helper(res,root.right); res.add(root.val); } }
145. Binary Tree Postorder Traversal
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原文地址:http://www.cnblogs.com/Machelsky/p/5941214.html