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145. Binary Tree Postorder Traversal

时间:2016-10-09 13:04:26      阅读:124      评论:0      收藏:0      [点我收藏+]

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Given a binary tree, return the postorder traversal of its nodes‘ values.

For example:
Given binary tree {1,#,2,3},

   1
         2
    /
   3

 

return [3,2,1].

 思路:后序遍历

/**
 * Definition for a binary tree node.
 * public class TreeNode {
 *     int val;
 *     TreeNode left;
 *     TreeNode right;
 *     TreeNode(int x) { val = x; }
 * }
 */
public class Solution {
    public List<Integer> postorderTraversal(TreeNode root) {
        List<Integer> res=new ArrayList<>();
        if(root==null){
            return res;
        }
        helper(res,root);
        return res;
    }
    public void helper(List<Integer> res,TreeNode root){
        if(root==null){
            return;
        }
        helper(res,root.left);
        helper(res,root.right);
        res.add(root.val);
    }
}

 

145. Binary Tree Postorder Traversal

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原文地址:http://www.cnblogs.com/Machelsky/p/5941214.html

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