码迷,mamicode.com
首页 > 其他好文 > 详细

404. Sum of Left Leaves

时间:2016-10-12 13:32:32      阅读:124      评论:0      收藏:0      [点我收藏+]

标签:

Find the sum of all left leaves in a given binary tree.

Example:

    3
   /   9  20
    /     15   7

There are two left leaves in the binary tree, with values 9 and 15 respectively. Return 24.

 

 

Hide Company Tags
 Facebook
Show Tags
 
/**
 * Definition for a binary tree node.
 * public class TreeNode {
 *     int val;
 *     TreeNode left;
 *     TreeNode right;
 *     TreeNode(int x) { val = x; }
 * }
 */
public class Solution {
    int sum = 0;
    public int sumOfLeftLeaves(TreeNode root) {
        if(root == null) return 0;
        return getleft(root, false);
    }
    public int getleft(TreeNode root, boolean isLeft){
        if(root == null) return 0;
        if(root.left == null && root.right == null && isLeft) return root.val;
        return  getleft(root.left ,true) + getleft(root.right, false);
    }
}

 

404. Sum of Left Leaves

标签:

原文地址:http://www.cnblogs.com/joannacode/p/5952215.html

(0)
(0)
   
举报
评论 一句话评论(0
登录后才能评论!
© 2014 mamicode.com 版权所有  联系我们:gaon5@hotmail.com
迷上了代码!