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Find the sum of all left leaves in a given binary tree.
Example:
3 / 9 20 / 15 7 There are two left leaves in the binary tree, with values 9 and 15 respectively. Return 24.
/** * Definition for a binary tree node. * public class TreeNode { * int val; * TreeNode left; * TreeNode right; * TreeNode(int x) { val = x; } * } */ public class Solution { int sum = 0; public int sumOfLeftLeaves(TreeNode root) { if(root == null) return 0; return getleft(root, false); } public int getleft(TreeNode root, boolean isLeft){ if(root == null) return 0; if(root.left == null && root.right == null && isLeft) return root.val; return getleft(root.left ,true) + getleft(root.right, false); } }
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原文地址:http://www.cnblogs.com/joannacode/p/5952215.html