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来一发高精度模板,感谢光勋的兹次!
const int _bod_=10000; struct BN{ static const int N=1010;int a[N]; BN(){memset(a,0,sizeof(a));} int& operator [](int n){return a[n];} BN operator =(int n){ memset(a,0,sizeof(a)); a[1]=n;if(a[1])a[0]=1; while(a[a[0]+1]){a[a[0]+1]=a[a[0]]/_bod_;a[a[0]++]%=_bod_;} return *this; } bool operator <(BN b) const{ if(a[0]<b[0])return 1; if(a[0]>b[0])return 0; for(int i=a[0];i>=1;i--){ if(a[i]>b[i])return 0; if(a[i]<b[i])return 1; } return 0; } BN operator +(BN b) const{ b[0]=max(a[0],b[0]); for(int i=1;i<=b[0];i++){ b[i]+=a[i]; if(b[i]>=_bod_){b[i+1]+=b[i]/_bod_;b[i]%=_bod_;} } if(b[b[0]+1])b[0]++; return b; } BN operator -(BN b) const{ BN ans=*this;int q=1; if(ans<b)swap(ans,b),q=-1; for(int i=1;i<=ans[0];i++){ ans[i]=ans[i]-b[i]; if(ans[i]<0){ans[i+1]--;ans[i]+=_bod_;} } while(ans[0]&&!ans[ans[0]])ans[0]--; for(int i=1;i<=ans[0];i++)ans[i]*=q; return ans; } BN operator *(BN b) const{ BN ans; ans[0]=a[0]+b[0]-1; for(int i=1;i<=a[0];i++) for(int o=1;o<=b[0];o++){ int now=i+o-1; ans[now]+=a[i]*b[o]; } for(int i=1;i<=ans[0];i++)if(ans[i]>=_bod_){ans[i+1]+=ans[i]/_bod_;ans[i]%=_bod_;} if(ans[ans[0]+1])ans[0]++; return ans; } void operator +=(BN b){*this=*this+b;} void operator -=(BN b){*this=*this-b;} void operator *=(BN b){*this=*this*b;} void print(){printf("%d",a[a[0]]);for(int i=a[0]-1;i>=1;i--)printf("%.4d",a[i]);}//.xd x=_bod_后导零的个数(位数) };
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原文地址:http://www.cnblogs.com/YJinpeng/p/5953779.html