作业4

#include <stdio.h>
int main()
{
    int i,sum = 0;
    for(i=1;i<=100;i++)
        sum += i;
    printf("sum=%d\n",sum);
    return 0;
}

#include <stdio.h>
int main()
{
    int i = 1,sum = 0;
    while(i<=100){
        sum = sum+i;
        i++;
    }
    printf("sum=%d\n",sum);
    return 0;
}

#include <stdio.h>
int main()
{
    int i,sum;
    i=1;sum = 0;
    while(i<=100){
        sum = sum + i;
        i++;
    }
    printf("sum=%d\n",sum);
    return 0;
}

#include <stdio.h>
int main()
{
    int i,n,jiec=1;
    printf("请输入一个整数n:");
    scanf("%d",&n);
    i = n;
    while(i>=1){
        jiec=jiec*i;
        i--;
    }
    printf("%d!=%d\n",n,jiec);
    return 0;
}

#include <stdio.h>
int main()
{
    int i,n,jiec=1;
    printf("请输入一个整数n:");
    scanf("%d",&n);
    i=n;
    do{
        jiec=jiec*i;
        i--;
    }while(i>=1);
    printf("%d!=%d\n",n,jiec);
    return 0;
}

#include <stdio.h>
int main()
{
    int i,n,jiec=1;
    printf("请输入一个整数n:");
    scanf("%d",&n);
    jiec=1;
    for(i=1;i<=n;i++){
        jiec=jiec*i;
    }
    printf("%d!=%d\n",n,jiec);
    return 0;
}

#include <stdio.h>
int main()
{
    int k,sum=0,i,a=1,b=0;
    float c,d=0,e=0;
    for(k=1;k<=100;k++)
        sum+=k;
    for(i=1;i<=50;i++)
    　　a=i*i;
    　　b=b+a;
    for(c=1;c<=10;c++)
        d=d+1/c;
        e=sum+c+d;
    printf("所求和为；%f\n",e);
    return 0;
}

#include <stdio.h>
int main()
{
    char c;
    int zm=0,sz=0,kg=0,qt=0;
    while((c=getchar())!=‘\n‘){
        if(c>=‘a‘&&c<=‘z‘||c>=‘A‘&&c<=‘Z‘)
            zm++;
        else if(c==‘ ‘)
            kg++;
        else
            qt++;
    }
    printf("字母个数：%d\n",zm);
    printf("空格个数：%d\n",kg);
    printf("其他个数：%d\n",qt);
    return 0;
}

#include <stdio.h>
int main()
{
    int m,n,t,i,gys=1,gbs; 
    printf("请输入两个整数：");
    scanf("%d%d",&m,&n);
    if(n>m){
        t=m;
        m=n;
        n=t;
    }
    for(i=n;i>=1;i--)
        if(m%i==0&&n%i==0)
            break;
        printf("m=%d,n=%d",m,n);
    if(i!=0){
        gys=i;
        printf("最大公约数为：%d\n",gys);
    }
    gbs = m*n/gys;
    printf("最小公倍数为：%d\n",gbs);
    return 0;
} 

#include<stdio.h>
int main(){
    int n,k1,k2,k3;
    for(k1=0;k1<=9;k1++)
    for(k2=0;k2<=9;k2++)
    for(k3=1;k3<=9;k3++){
    if(k3*100+k2*10+k1==k1*k1*k1+k2*k2*k2+k3*k3*k3)
    　　printf("%d\n",k3*100+k2*10+k1);
    }
    return 0;
}