码迷,mamicode.com
首页 > 其他好文 > 详细

Flip Game

时间:2016-10-15 07:42:34      阅读:322      评论:0      收藏:0      [点我收藏+]

标签:

You are playing the following Flip Game with your friend: Given a string that contains only these two characters: + and -, you and your friend take turns to flip two consecutive "++" into "--". The game ends when a person can no longer make a move and therefore the other person will be the winner.

Write a function to compute all possible states of the string after one valid move.

For example, given s = "++++", after one move, it may become one of the following states:

[
  "--++",
  "+--+",
  "++--"
]

 

If there is no valid move, return an empty list [].

 

 1 class Solution {
 2 public:
 3     vector<string> generatePossibleNextMoves(string s) {
 4         vector<string> result;
 5         if (s.size() < 2) return result;
 6         
 7         for (int i = 1; i < s.size(); i++) {
 8             if (s[i] == + && s[i - 1] == +) {
 9                 s[i] = s[i - 1] = -;
10                 result.push_back(s);
11                 s[i] = s[i - 1] = +;
12             } 
13         }
14         return result;
15     }
16 };

 

Flip Game

标签:

原文地址:http://www.cnblogs.com/amazingzoe/p/5962688.html

(0)
(0)
   
举报
评论 一句话评论(0
登录后才能评论!
© 2014 mamicode.com 版权所有  联系我们:gaon5@hotmail.com
迷上了代码!