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Sum Root to Leaf Numbers

时间:2014-08-13 18:17:26      阅读:208      评论:0      收藏:0      [点我收藏+]

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Given a binary tree containing digits from 0-9 only, each root-to-leaf path could represent a number.

An example is the root-to-leaf path 1->2->3 which represents the number 123.

Find the total sum of all root-to-leaf numbers.

For example,

    1
   /   2   3

The root-to-leaf path 1->2 represents the number 12.

The root-to-leaf path 1->3 represents the number 13.

Return the sum = 12 + 13 = 25.

思路:本题本质上是要对二叉树进行遍历。我们使用递归对二叉树进行深度优先遍历。

 1 class Solution {
 2 public:
 3     int sumNumbers( TreeNode *root ) {
 4         if( !root ) { return 0; }
 5         return sumSub( root, 0 );
 6     }
 7 private:
 8     int sumSub( TreeNode *node, int num ) {
 9         num = 10*num + node->val;
10         if( !node->left && !node->right ) { return num; }
11         int left = 0, right = 0;
12         if( node->left ) { left = sumSub( node->left, num ); }
13         if( node->right ) { right = sumSub( node->right, num ); }
14         return left + right;
15     }
16 };

 

Sum Root to Leaf Numbers,布布扣,bubuko.com

Sum Root to Leaf Numbers

标签:style   blog   color   使用   io   for   ar   div   

原文地址:http://www.cnblogs.com/moderate-fish/p/3910351.html

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