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http://codeforces.com/problemset/problem/731/A
每次操作总共4种情况,判断一下就好了。
#include<iostream> #include<cstring> #include<cstdio> #include<algorithm> using namespace std; char s[105]; int main() { int cnt = 0; char now = ‘a‘; scanf("%s",s); int len = strlen(s); for(int i = 0;i < len;i++) { if(now <= s[i]) cnt += min(s[i]-now,now+26-s[i]); else cnt += min(now-s[i],s[i]+26-now); now = s[i]; } printf("%d\n",cnt); return 0; }
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原文地址:http://www.cnblogs.com/zhurb/p/5968287.html