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直接模拟即可。
// codevs3716 #include<algorithm> #include<iostream> #include<cstdlib> #include<cstring> #include<cstdio> #include<cmath> #define LL long long #define MOD 1000000007 #define inf 2147483640 #define Pi acos(-1.0) #define free(a) freopen(a".in","r",stdin),freopen(a".out","w",stdout); using namespace std; const int maxn=2000; int c[5][5]={{0,0,1,1,0}, {1,0,0,1,0}, {0,1,0,0,1}, {0,0,1,0,1}, {1,1,0,0,0}}; int a[maxn],b[maxn]; int main() { int n,na,nb; scanf("%d%d%d",&n,&na,&nb); for (int i=0;i<na;i++) scanf("%d",&a[i]); for (int i=0;i<nb;i++) scanf("%d",&b[i]); int A=0,B=0; for (int i=0;i<n;i++) { A+=c[a[i%na]][b[i%nb]]; B+=c[b[i%nb]][a[i%na]]; } printf("%d %d",A,B); return 0; }
一开始无脑枚举,因为只需要dfs1层,感觉完全不虚,结果被菊花树卡得只有70分,于是怒水一发树形dp。
// codevs3728 #include<algorithm> #include<iostream> #include<cstdlib> #include<cstring> #include<cstdio> #include<cmath> #define LL long long #define MOD 10007 #define inf 2147483640 #define Pi acos(-1.0) #define free(a) freopen(a".in","r",stdin),freopen(a".out","w",stdout); using namespace std; const int maxn=200010; struct edge {int to,next;}e[maxn<<1]; int head[maxn],n,cnt,w[maxn],ans1,ans2;; void link(int u,int v) { e[++cnt].to=v;e[cnt].next=head[u];head[u]=cnt; e[++cnt].to=u;e[cnt].next=head[v];head[v]=cnt; } void dfs(int x,int fa,int f) { ans1=(ans1+w[x]*w[f]);ans2=max(ans2,w[x]*w[f]); int x1=0,x2=0; for (int i=head[x];i;i=e[i].next) if (e[i].to!=fa) { dfs(e[i].to,x,fa); ans2=max(ans2,x2*w[e[i].to]); ans1=(ans1+x1*w[e[i].to])%MOD; x1=(x1+w[e[i].to])%MOD;x2=max(x2,w[e[i].to]); } } int main() { scanf("%d",&n); for (int u,v,i=1;i<n;i++) { scanf("%d%d",&u,&v); link(u,v); } for (int i=1;i<=n;i++) scanf("%d",&w[i]); dfs(1,0,0); printf("%d %d",ans2,ans1*2%MOD); return 0; }
一开始打了个nm²加队列乱搞可以获得85分的高分哦!正解背包。
// codevs3729 #include<algorithm> #include<iostream> #include<cstdlib> #include<cstring> #include<cstdio> #include<cmath> #define LL long long #define inf 100000000 #define Pi acos(-1.0) #define free(a) freopen(a".in","r",stdin),freopen(a".out","w",stdout); using namespace std; const int maxn=10010,maxm=1010; struct data {int p,l,r;}t[maxn]; int n,m,K,u[maxn],d[maxn],l[maxn],r[maxn],f[maxn][maxm]; int main() { scanf("%d%d%d",&n,&m,&K); for (int i=0;i<n;i++) scanf("%d%d",&u[i],&d[i]); for (int i=0;i<=n;i++) l[i]=0,r[i]=m+1; for (int x,i=1;i<=K;i++) { scanf("%d",&x); scanf("%d%d",&l[x],&r[x]); } int cnt=0; for (int i=1;i<=n;i++) { for (int j=1;j<=m;j++) { f[i][j]=inf; if (j>u[i-1]) f[i][j]=min(f[i][j],min(f[i-1][j-u[i-1]],f[i][j-u[i-1]])+1); } for (int j=m-u[i-1];j<=m;j++) f[i][m]=min(f[i][m],min(f[i-1][j],f[i][j])+1); for (int j=l[i]+1;j<=r[i]-1;j++) if (j+d[i-1]<=m) f[i][j]=min(f[i][j],f[i-1][j+d[i-1]]); for (int j=1;j<=l[i];j++) f[i][j]=inf; for (int j=r[i];j<=m;j++) f[i][j]=inf; int flag=0; for (int j=1;j<=m;j++) if (f[i][j]<inf) {flag=1;break;} if (!flag) {printf("0\n%d",cnt);return 0;} else if (r[i]!=m+1) cnt++; } int ans=inf; for (int i=1;i<=m;i++) ans=min(ans,f[n][i]); printf("1\n%d",ans); return 0; }
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原文地址:http://www.cnblogs.com/MashiroSky/p/5983029.html