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24. Swap Nodes in Pairs

时间:2016-10-30 07:31:50      阅读:218      评论:0      收藏:0      [点我收藏+]

标签:ini   constant   span   ant   algorithm   value   nbsp   color   amp   

Given a linked list, swap every two adjacent nodes and return its head.

For example,
Given 1->2->3->4, you should return the list as 2->1->4->3.

Your algorithm should use only constant space. You may not modify the values in the list, only nodes itself can be changed.

 

/**
 * Definition for singly-linked list.
 * public class ListNode {
 *     int val;
 *     ListNode next;
 *     ListNode(int x) { val = x; }
 * }
 */
public class Solution {
    public ListNode swapPairs(ListNode head) {
        if(head == null || head.next == null){
            return head;
        }
        ListNode dummy = new ListNode(0);
        dummy.next = head;
        ListNode cur = dummy;
        while(cur != null && cur.next != null && cur.next.next != null){
            ListNode slow = cur.next;
            ListNode fast =  cur.next.next;
            slow.next = fast.next;
            cur.next = fast;
            cur.next.next = slow;
            cur = slow;
        }
        return dummy.next;
    }
}

 

24. Swap Nodes in Pairs

标签:ini   constant   span   ant   algorithm   value   nbsp   color   amp   

原文地址:http://www.cnblogs.com/joannacode/p/6012364.html

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