标签:for names span pre while gif i++ blocks str
这是一道dp……
f [ i ] [ j ] 表示前 i 组,总和为 j 时的方案数
f [ i ] [ j + a [ i ] [ k ] ] <-- f [ i - 1 ] [ j ]
1 #include<cstdio> 2 #include<cstring> 3 #include<algorithm> 4 using namespace std; 5 const int N=105,M=11000; 6 int f[N][M],a[N][N],maxl[N],maxn,n,Q; 7 int main(){ 8 maxn=0; 9 scanf("%d %d",&n,&Q); 10 for (int i=1;i<=n;i++){ 11 scanf("%d",&a[i][0]); 12 for (int j=1;j<=a[i][0];j++){ 13 scanf("%d",&a[i][j]); 14 if (a[i][j]>maxl[i]) 15 maxl[i]=a[i][j]; 16 } 17 maxn+=maxl[i]; 18 sort(a[i]+1,a[i]+a[i][0]+1); 19 } 20 for (int i=1;i<=a[1][0];i++) 21 f[1][a[1][i]]++;//初始化不能赋成1 22 for (int i=2;i<=n;i++) 23 for (int j=1;j<=maxn;j++){ 24 if (!f[i-1][j]) 25 continue; 26 for (int k=1;k<=a[i][0];k++) 27 f[i][j+a[i][k]]+=f[i-1][j]; 28 } 29 int p=1,j=0; 30 while (p<=Q){ 31 j++; 32 for (int i=1;i<=f[n][j];i++){ 33 if (p>Q) return 0; 34 printf("%d ",j); 35 p++; 36 } 37 } 38 return 0; 39 }
标签:for names span pre while gif i++ blocks str
原文地址:http://www.cnblogs.com/Absolute-Zero/p/6012600.html