标签:size 二叉树 path imu tco i++ while art .com
Given a binary tree, find its maximum depth.
The maximum depth is the number of nodes along the longest path from the root node down to the farthest leaf node.
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计算二叉树的深度
java(3ms):bfs
1 /** 2 * Definition for a binary tree node. 3 * public class TreeNode { 4 * int val; 5 * TreeNode left; 6 * TreeNode right; 7 * TreeNode(int x) { val = x; } 8 * } 9 */ 10 public class Solution { 11 public int maxDepth(TreeNode root) { 12 if (root == null) 13 return 0 ; 14 int depth = 0 ; 15 TreeNode node = null ; 16 Queue<TreeNode> que = new LinkedList<TreeNode>() ; 17 que.offer(root) ; 18 while(!que.isEmpty()){ 19 int size = que.size() ; 20 for (int i = 0 ; i < size ; i++){ 21 node = que.poll() ; 22 if (node.left != null){ 23 que.offer(node.left) ; 24 } 25 if (node.right != null){ 26 que.offer(node.right) ; 27 } 28 29 } 30 depth++ ; 31 } 32 return depth; 33 } 34 }
java(1ms):dfs
1 /** 2 * Definition for a binary tree node. 3 * public class TreeNode { 4 * int val; 5 * TreeNode left; 6 * TreeNode right; 7 * TreeNode(int x) { val = x; } 8 * } 9 */ 10 public class Solution { 11 public int maxDepth(TreeNode root) { 12 if (root == null) 13 return 0 ; 14 15 return Math.max(maxDepth(root.left),maxDepth(root.right)) + 1 ; 16 } 17 }
104. Maximum Depth of Binary Tree
标签:size 二叉树 path imu tco i++ while art .com
原文地址:http://www.cnblogs.com/-Buff-/p/6014340.html