标签:思路 ons more ace sse lua 集合 repeat zed
Pack consecutive duplicates of list elements into sublists. If a list contains repeated elements they should be placed in separate sublists. Example: scala> pack(List(‘a, ‘a, ‘a, ‘a, ‘b, ‘c, ‘c, ‘a, ‘a, ‘d, ‘e, ‘e, ‘e, ‘e)) res0: List[List[Symbol]] = List(List(‘a, ‘a, ‘a, ‘a), List(‘b), List(‘c, ‘c), List(‘a, ‘a), List(‘d), List(‘e, ‘e, ‘e, ‘e))
题目描述: 如果一个list中有相同的元素,则将相同的元素放到一个新的list中,最后返回list[list]
scala List span 函数:
定义:
final def span(p: (A) ? Boolean): (List[A], List[A]) Splits this list into a prefix/suffix pair according to a predicate. Note: c span p is equivalent to (but possibly more efficient than) (c takeWhile p, c dropWhile p), provided the evaluation of the predicate p does not cause any side-effects. returns a pair consisting of the longest prefix of this list whose elements all satisfy p, and the rest of this list. Definition Classes List → LinearSeqOptimized → TraversableLike → GenTraversableLike Annotations @inline()
即span 根据输入的bool表达式,将list进行分割。返回一个list集合。但是碰到第一个不满足的元素,即返回。如:
list 的partition: 会遍历所有元素。
思路: 题目的要求是,连续的相等的元素放到同一个 list中,因此
使用span 进行分割。
def packList[T](a:List[T]): List[List[T]] = { def _pack(res:List[List[T]], tmp:List[T]):List[List[T]] = { tmp match{ case Nil => res case ls =>{ val (s:List[T], r:List[T]) = tmp span{_ == tmp.head} _pack(res:::List(s), r) } } } _pack(List(), a) }
标签:思路 ons more ace sse lua 集合 repeat zed
原文地址:http://www.cnblogs.com/missmzt/p/6031324.html