码迷,mamicode.com
首页 > 其他好文 > 详细

POJ 3461 Oulipo(KMP字符串匹配)

时间:2014-08-14 20:36:39      阅读:248      评论:0      收藏:0      [点我收藏+]

标签:acm   dp   poj   kmp   字符串   

题意  给你两个字符串p和s  求p在s中出现的次数  很裸的kmp

因为不止匹配一次  每次找到后还要循环j=next[j]的过程   知道到达s的终点

#include<cstdio>
#include<cstring>
using namespace std;
const int N = 10005, M = 1000005;
int next[N], ans, n;
char p[N], s[M];

void kmp ()
{
    int lp = strlen (p), ls = strlen (s), i, j;
    next[0] = -1, next[1] = i = 0;
    while ( (++i) < lp)
    {
        j = next[i];
        while (j != -1 && p[i] != p[j])
            j = next[j];
        next[i + 1] = j + 1;
    }

    i = j = 0;
    while (i < ls)
    {
        if (j == -1 || s[i] == p[j])
        {
            ++i, ++j;
            if (j == lp) ++ans, j = next[j];
        }
        else j = next[j];
    }
}

int main()
{
    scanf ("%d", &n);
    while (n--)
    {
        ans = 0;
        scanf ("%s%s", p, s);
        kmp ();
        printf ("%d\n", ans);
    }
    return 0;
}

Oulipo

Description

The French author Georges Perec (1936–1982) once wrote a book, La disparition, without the letter ‘e‘. He was a member of the Oulipo group. A quote from the book:

Tout avait Pair normal, mais tout s’affirmait faux. Tout avait Fair normal, d’abord, puis surgissait l’inhumain, l’affolant. Il aurait voulu savoir où s’articulait l’association qui l’unissait au roman : stir son tapis, assaillant à tout instant son imagination, l’intuition d’un tabou, la vision d’un mal obscur, d’un quoi vacant, d’un non-dit : la vision, l’avision d’un oubli commandant tout, où s’abolissait la raison : tout avait l’air normal mais…

Perec would probably have scored high (or rather, low) in the following contest. People are asked to write a perhaps even meaningful text on some subject with as few occurrences of a given “word” as possible. Our task is to provide the jury with a program that counts these occurrences, in order to obtain a ranking of the competitors. These competitors often write very long texts with nonsense meaning; a sequence of 500,000 consecutive ‘T‘s is not unusual. And they never use spaces.

So we want to quickly find out how often a word, i.e., a given string, occurs in a text. More formally: given the alphabet {‘A‘‘B‘‘C‘, …, ‘Z‘} and two finite strings over that alphabet, a word W and a text T, count the number of occurrences of W in T. All the consecutive characters of W must exactly match consecutive characters of T. Occurrences may overlap.

Input

The first line of the input file contains a single number: the number of test cases to follow. Each test case has the following format:

  • One line with the word W, a string over {‘A‘‘B‘‘C‘, …, ‘Z‘}, with 1 ≤ |W| ≤ 10,000 (here |W| denotes the length of the string W).
  • One line with the text T, a string over {‘A‘‘B‘‘C‘, …, ‘Z‘}, with |W| ≤ |T| ≤ 1,000,000.

Output

For every test case in the input file, the output should contain a single number, on a single line: the number of occurrences of the word W in the text T.

Sample Input

3
BAPC
BAPC
AZA
AZAZAZA
VERDI
AVERDXIVYERDIAN

Sample Output

1
3
0


POJ 3461 Oulipo(KMP字符串匹配),布布扣,bubuko.com

POJ 3461 Oulipo(KMP字符串匹配)

标签:acm   dp   poj   kmp   字符串   

原文地址:http://blog.csdn.net/iooden/article/details/38563023

(0)
(0)
   
举报
评论 一句话评论(0
登录后才能评论!
© 2014 mamicode.com 版权所有  联系我们:gaon5@hotmail.com
迷上了代码!